LEET code--Add Digits

Add Digits

 Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

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int addDigits(int num) { while(num>=10){ int temp=0; while(num!=0){ temp+=num%10; num/=10; } num=temp; } return num; }